You are given this formula. It is describing the oxidation (or burning) of octane (a major component in gasoline). The result is the release of carbon dioxide and water.
2 C8H18(l) + 25 O2(g) à 16 CO2(g) + 18 H2O(g)
Question #1: If you started out with 10 moles of O2, how many moles of CO2 would you get if the reaction goes to completion? How much is that in grams?
Question #2: Why do some car manufacturers ask that you use Octane 91, instead of 87? If the manufacturer recommends that you use regular 87 Octane, would it help your engine if you were to use 91?